Problem
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
Solution
Python :
def solve():
sum = 0
for x in range(1000):
if((x%3==0) or (x%5==0)):
sum += x
return sum
if __name__ == "__main__":
print(solve())